If a spring has a constant of 7 (kg)/s^2, how much work will it take to extend the spring by 21 cm ?

1 Answer
IDKwhatName
Jul 23, 2017

0.31J

Explanation:

F=kDeltax, and W=FDeltas, where:
Deltax=Deltas = extension/distance travelled in the direction of the force (m)
F = force (N)
W = Work done (Nm)
k = spring constant (N m^(-1))

Therefore, W=k(Deltax)(Deltax)=k(Deltax)^2=7*0.21^2=0.3087~~0.31J

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