Question

If a spring has a constant of `7 (kg)/s^2`, how much work will it take to extend the spring by `21 cm`?

Answer 1

`0.31J`

Explanation:

`F=kDeltax`, and `W=FDeltas`, where:
`Deltax=Deltas` = extension/distance travelled in the direction of the force (`m`)
`F` = force (`N`)
`W` = Work done (`Nm`)
`k` = spring constant (`N` `m^(-1)`)

Therefore, `W=k(Deltax)(Deltax)=k(Deltax)^2=7*0.21^2=0.3087~~0.31J`