Question

How do you factor and simplify `\frac { x ^ { 2} + 2x - 8} { x ^ { 2} - 9} \times \frac { x + 3} { x + 4}`?

Answer 1

`(x-2)/(x+3)`

Explanation:

`(x^2+2x-8)/(x^2-9) * (x+3)/(x+4)`

This factors out to `[cancel((x+4))(x-2)]/[(x-3)cancel((x+3))] * cancel(x+3)/cancel(x+4)`

This simplifies to `(x-2)/(x+3)`