Question #9a474

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Question #9a474

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Answer 1 · 2017-07-26T21:09:40

$.037037037$ $.037037037$

Explanation:

We are given the probability that a student will pass an exam $\frac{2}{3}$ $2/3$ of the time. This means that the student will fail an exam $\frac{1}{3}$ $1/3$ of the time.

Now we are given the scenario of the student failing $3$ $3$ exams consecutively. So, we will multiply $\frac{1}{3}$ $1/3$ three times.

$\frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = .037037037$ $1/3xx1/3xx1/3=.037037037$

We can say that there's a . $037037037$ $037037037$ chance of the student failing three exams back to back.

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Question #9a474

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