How do you simplify #\frac { 7y ^ { 6} } { 21y ^ { 2} }#?

1 Answer
Tsepi
Jul 31, 2017

The answer is #y^4/3#

Explanation:

  1. Simplifying the numbers.
    #7/21# has a common factor of 7, so it simplifies to #1/3#

  2. Simplifying the variables.
    Division of exponents is done by subtracting the denominator's exponent from the numerator's exponent, i.e.
    #a^x/a^y# =#a^(x-y)#

So in this case, it'll be #y^(6-2)#=#y^4#

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