Question #81c91

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Question #81c91

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Answer 1 · 2017-08-02T15:35:05

$x = 0 or x = \frac{3}{2}$ $x=0" or " x=3/2$

Explanation:

$take out a common factor of x from both terms$ $"take out a "color(blue)"common factor"" of x from both terms"$

$\Rightarrow x (2 x - 3) = 0$ $rArrx(2x-3)=0$

$\Rightarrow x = 0 or 2 x - 3 = 0 \Rightarrow x = \frac{3}{2}$ $rArrx=0" or " 2x-3=0rArrx=3/2$

Answer 2 · 2017-08-02T15:42:20

$x_{1} = 0$ $x_1 = 0$
$x_{2} = \frac{2}{3}$ $x_2 = 2/3$

Explanation:

First of all, factorise " $x$ $x$ "

$\Rightarrow x (2 x - 3) = 0$ $=> x(2x-3)=0$

Then, as you may know, when product of factors equals 0 then one factor is equal 0

$\Rightarrow$ $=>$ $x = 0$ $x=0$
$2 x - 3 = 0$ $2x-3=0$

Solve then the equation $2 x - 3 = 0$ $2x-3=0$

$\Rightarrow 2 x = 0 + 3 \Rightarrow 2 x = 3$ $=> 2x=0+3 => 2x=3$

$x = \frac{3}{2}$ $x=3/2$ (or 1.5)

It gives us finally

$x_{1} = 0$ $x_1 = 0$
$x_{2} = \frac{3}{2}$ $x_2 = 3/2$

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Question #81c91

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