How do you evaluate #-2i ( - 2+ 3i )#?
1 Answer
Aug 2, 2017
Explanation:
To evaluate this, distribute
#-2i(-2+3i)#
#(-2i)(-2)+(-2i)(3i)#
#4i+(-6i^2)#
#4i-6i^2#
Since we know that
#4i-6(-1)#
#4i+6#
Rewriting this in