Question #9b04c

2 Answers
Aug 5, 2017

#log_10(1000)=3#

Explanation:

I'm assuming that you mean log with base 10. The answer will be different if the base is not 10.

Here are two ways of writing the same expression:

#y=log_10(x)#

and

#10^y=x#

#y="the power"#

#10="the base"#

#x="the answer"#

We need to solve for the power, #y#. Start with the log form:

#y=log_10(1000)#

Rewrite this expression in index form:

#10^y=1000#

Rewrite the expression with the same base on both sides:

#10^y=10^3#

Because we have the same base, the powers must be equal:

#y=3#

So #log_10(1000)=3#

See if you can find another way of solving this problem using the following log laws:

#log_a(b^n)=nlog_a(b)#

#log_a(a)=1#

Aug 5, 2017

#log(1000)=3#

Explanation:

Usually #log# stands for "logarithm base 10" or #log_10#

A logarithm is a function that returns the power to which you must take the base to get the input.

Or in the case of base 10

#log(10^x)=x#

and for any base #b#

#log_b(b^x)=x#

Since #1000=100times10# and #100=10times10#,

then #1000=10times10times10#

And by the definition of an exponent

#1000=10times10times10=10^3#

Then

#log(1000)=log(10^3)=3#