How do you use the point on the line and the slope of the line to find three additional points through which the line passes: Point: (5, -6) Slope: m = 1?

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Answer 1 · 2017-08-08T12:25:24

(0,-11), (4,-7) and (6,-5)

We first must construct a linear equation from which these point will lie on. This can be done using the formula

$(y - y_{1}) = m (x - x_{1})$ $(y-y_1)=m(x-x_1)$

$m$ $m$ would be the gradient of the graph, which we have; $m = 1$ $m=1$

$x_{1} and y_{1}$ $x_1 and y_1$ are a point on the graph, which we are given; $x_{1} = 5$ $x_1=5$ and $y_{1} = - 6$ $y_1=-6$

Thus, we will get a linear equation of

$(y - (- 6)) = 1 (x - (5))$ $(y-(-6))=1(x-(5))$

$(y + 6) = (x - 5)$ $(y+6)=(x-5)$

$y = x - 11$ $y=x-11$

graph{y=x-11 [-17.41, 22.59, -15.04, 4.96]}

Now, we can substitute values for x and y to find 3 additional points that lie on this line.