Question

How do you calculate `(2+3i)*(-3-2i)`?

Answer 1

Open brackets and multiply.

Explanation:

This is how you'll proceed ,treat 'i'(iota) as a variable:
`2(-3-2i)+3i(-3-2i)`
`=-6-4i-9i-6i^2`
`=-13i (because i^2=-1, so -6i^2=-6*-1=6)`
Therefore answer is `-13i`