How do you solve $- \frac{3}{4} j \geq 12$ $-3/4j>=12$ ?

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Answer 1 · 2017-08-10T12:29:14

$j \leq - 16$ $j <= -16$

$- \frac{3}{4} j \geq 12$ $-3/4j ≥ 12$

$j \leq \frac{12}{(- \frac{3}{4})}$ $j <= 12/((-3/4))$

$j \leq 12 \times - \frac{4}{3}$ $j <= 12 xx -4/3$

$j \leq - 16$ $j <= -16$

How do you solve −34j≥12-3/4j>=12?