Question #31b2f
3 Answers
Aug 10, 2017
Please see below.
Explanation:
# = (cosx+sinx)/(cosx-sinx)#
# = ((2sinx))/((2sinx)) * ((cosx+sinx))/((cosx-sinx))#
# = (2sinxcosx+2sin^2x)/(2sinxcosx-2sin^2x)#
# = (sin2x+1-1+2sin^2x)/(sin2x -1+1-2sin^2x)#
# = (sin2x+1-(1-2sin^2x))/(sin2x -1+(1-2sin^2x))#
# = (sin2x+1-cos2x)/(sin2x -1+cos2x)#
Aug 11, 2017
Answer is below
Explanation:
![https://useruploads.socratic.org/nTwt7AcSTii8k1VoQILa_IMG-20170811-WA0009.jpg)
Aug 11, 2017
Refer to a Proof in the Explanation.
Explanation:
Knowing that,
By, Componendo-Dividendo, then, we get,
Hence, the Proof.
Enjoy Maths!