How do you solve $9 (p - 4) = 18$ $9( p - 4) = 18$ ?

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Answer 1 · 2017-08-13T02:07:13

Expand lhs
9p-36 = 18
Add 36 to both sides
9p = 54

Divide both sides by 9
P = 54/9

P= 6

Answer 2 · 2017-08-13T02:08:19

$p = 6$ $p=6$

Begin by distributing $9$ $9$ to $p$ $p$ and $- 4$ $-4$

$(9 \cdot p) + (9 \cdot - 4) = 18$ $(9*p)+(9*-4)=18$

$9 p \pm 36 = 18$ $9p+-36=18$

$9 p - 36 = 18$ $9p-36=18$

Add $36$ $36$ to both sides:

$9 p - 36 + 36 = 18 + 36$ $9p-36color(red)(+36)=18color(red)(+36)$

$9 p = 54$ $9p=54$

Divide $9$ $9$ from both sides to isolate the variable and solve for $p$ $p$

$\frac{9}{9} p = \frac{54}{9}$ $9/color(red)9p=54/color(red)9$

$p = 6$ $p=6$

How do you solve 9(p−4)=189( p - 4) = 18?