Question #156df

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Question #156df

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Answer 1 · 2017-08-14T02:25:51

$x \in (- \infty, \infty)$ $x in (-oo,oo)$
$y \in (4, \infty)$ $yin (4,oo)$

Explanation:

Given $y = x^{2} + 4$ $y=x^2+4$
So if we are interested in finding maximum or natural domain of $x$ $x$ then $x$ $x$ can take any real value as for every real value of $x$ $x$ we get a real value of $y$ $y$ .

But as for any real number, the square of any real number is always non negative and hence
$x^{2} \geq 0$ $x^2>=0$
$\Rightarrow x^{2} + 4 \geq 4$ $=> x^2+4>=4$
$:. y>=4$

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Question #156df

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