How do you solve this system of equations: #y= - 3x + 1; 5x - 2= - y#?

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Answer 1 · 2017-08-14T14:28:07

See below

#x=1/2" " y=-1/2#

#y=−3x+1;5x−2=−y" "# this is the same as

#y=−3x+1"#
#−y=5x−2" "# Now add these two equations

#0=2x-1" " rArr1=2x" "# Divide both sides by #2#

#x=1/2" "# Substitute this into the first equation

#y=-3*1/2+1" "rArry=-1/2#

#x=1/2" " y=-1/2#