How do I find the domain of the function $y = \sqrt{2 x - 8}$ $y=sqrt(2x-8)$ ?

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Answer 1 · 2017-08-17T18:59:31

See below.

The value under a radical (square root) cannot be negative.

So, $2 x - 8 \geq 0$ $2x-8geq0$ , or $x \geq 4$ $xgeq4$ .

So, the domain of this function is $[4, \infty)$ $[4,oo)$ .

How do I find the domain of the function y=√2x−8y=sqrt(2x-8)?