Question #cfc6c

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Question #cfc6c

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Answer 1 · 2017-08-20T19:42:48

Speed $\times$ $xx$ time (not always)

Explanation:

Distance is how far on an object travels and it is equal to the speed of the object times by the time the object takes.

$d = s \times t$ $d= s xx t$

For example:
A golf cart is driven at its top speed of $27.0$ $27.0$ km/h for $10.0$ $10.0$ minutes. How far did the golf cart travel?
First, you convert the time to hours, because the speed is measured in hours.

$= \frac{10}{60} = 0.166667 h r$ $= 10/60= 0.166667hr$

$= 27.0 \times 0.166667$ $= 27.0 xx 0.166667$

$d = 4.5 k m$ $d= 4.5km$
You can use this triangle to help you find any of these three values, if you know the other two.
![http://www.softschools.com/formulas/physics/distance_speed_time_formula/75/]( useruploads.socratic.org )

However this formula is not the only formula we use to find distance. It depends on what information we know. This is just the basic.
There are other formulas like,
$s = \frac{1}{2} a t^{2}$ $s= 1/2at^2$
$s = V_{i} t + \frac{1}{2} a t^{2}$ $s= V_it+1/2at^2$

$s =$ $s=$ distance
$t =$ $t=$ time
$V_{i} =$ $V_i=$ initial speed
$a =$ $a=$ gravitational acceleration

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Question #cfc6c

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