How do you solve the system of equations $- 2 x + 3 y = 3$ $-2x + 3y = 3$ and $5 x - 6 y = - 3$ $5x - 6y = - 3$ ?

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Answer 1 · 2017-08-22T06:19:29

Multiply one of the equation so that you can rule out either the $x$ $x$ or the $y$ $y$ value, then add them up to actually let one of them vanish.

Multiply the first equation by $2$ $2$ , then add both equations up.

This gives: $- 4 x = 6 y = 6$ $-4x=6y=6$
Adding up: $1 x - 0 y = 3$ $1x-0y=3$ , simplified: $x = 3$ $x=3$ since $0 \times y = 0$ $0 times y =0$

How do you solve the system of equations −2x+3y=3-2x + 3y = 3 and 5x−6y=−35x - 6y = - 3?