Question #4d33a

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Question #4d33a

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Answer 1 · 2017-08-22T16:34:11

Option $(1)$ $(1)$ is correct.

Explanation:

If $V$ $V$ be the velocity with which the football is kicked, then

$K = \frac{1}{2} m V^{2}$ $K=1/2mV^2$

At highest point, $y -$ $y-$ component of velocity becomes zero, however, $x -$ $x-$ component remains constant. Therefore, kinetic energy, at highest point, is determined by $x -$ $x-$ component of velocity $V$ $V$ . Let $V_{x}$ $V_x$ and $K'$ represent $x-$ component of velocity and kinetic energy at highest point respectively.

$V_x=Vcos45=V/sqrt2$

Now, $K'=1/2mV_x^2=1/2m(V/sqrt2)^2=1/2mV^2/2=1/2(1/2mV^2)=1/2K=K/2$

Hence, option $(1)$ is correct.

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