Question

How do you simplify `\frac { 3c - 2d - 6} { - 24c ^ { - 3} d e ^ { 2} h - 7}`?

Answer 1

`-(c^3(c-2d-6))/(24de^2h+7c^3)`

Explanation:

Multiplying top and bottom by `c^3` to remove negative exponent in denominator.
`((3c-2d-6)/(-24c^-3de^2h-7))` `-> ((3c^4-2dc^3-6c^3)/(-24de^2h-7c^3))`

Factorising numerator and multiplying numerator and denominator by -1
- `(c^3(c-2d-6))/(24de^2h+7c^3)`