Question #73c96

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Question #73c96

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Answer 1 · 2017-08-22T21:23:54

I use a "model" like this: $\frac{T}{A 1} + \frac{T}{A 2} = 1$ $T/(A1)+T/(A2) =1$ where T = together time, and A1 and A2 represent the different alone times, and there is 1 job to be done.

Explanation:

Therefore, $(\frac{T}{8}) + (\frac{T}{4}) = 1$ $(T/8)+(T/4)=1$
Multiply both sides by 8: $8 (\frac{T}{8} + \frac{T}{4}) = (1) 8$ $8(T/8+T/4)=(1)8$

So, T + 2T = 8, 3T = 8, so T = $\frac{8}{3}$ $8/3$ hours or 2 and $\frac{2}{3}$ $2/3$ hours.

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Question #73c96

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