What is the heat absorbed by "27 g"27 g of water that increases in temperature by 58^@ "C"58C? Assume c = "4.184 J/g"^@ "C"c=4.184 J/gC for water in this temperature range.

1 Answer

Q = "6600 Joules"Q=6600 Joules

Explanation:

The heat QQ for a given mass mm of water with specific heat capacity c = "4.184 J/g"^@ "C"c=4.184 J/gC that increases in temperature by 58^@ "C"58C is given by:

Q = mcDeltaT

= ("27 g") cdot ("4.184 J"//"g"^@"C")(58^@"C") = "6552 J"

~~ "6600 J"