How do you find the derivative of #g(x)=1/sqrtx#? Calculus Basic Differentiation Rules Power Rule 1 Answer harsh s. Aug 23, 2017 see below Explanation: #g(x)=1/sqrtx# #=>d/dxg(x)=d/dx(x)^(-1/2)# Utilize the formula, #d/dxx^n=nx^(n-1)# #=>d/dx(x)^(-1/2)=-1/2x^((-1/2-1))=-1/(2xsqrtx)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1668 views around the world You can reuse this answer Creative Commons License