How do you write the function in standard form y=-7/3(x+6)(x+3)y=−73(x+6)(x+3)?

1 Answer
MrsRudolph221
Aug 24, 2017

Is standard form y = ax^2+bx+cax2+bx+c for you, or is
it y = a(x-h)^2+ka(x−h)2+k? I call the second equation "vertex" form.

Explanation:

So, take y = -7/3(x+6)(x+3)−73(x+6)(x+3) and expand by multiplication:

y = -7/3(x^2+9x+18)−73(x2+9x+18)

First, help with fractions: -7/3*9=-63/3=-21−73⋅9=−633=−21 and -7/3*18=-7*6 =-42−73⋅18=−7⋅6=−42.

Distribute: y = -7/3x^2-21x+(-42)−73x2−21x+(−42). This is what I call standard form.

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