Question #15209

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Answer 1 · 2017-08-25T16:35:47

$x = \frac{1}{A} (2 d + e + y)$ $x = frac(1)(A) (2 d + e + y)$

We have: $A x - y = 2 d + e$ $A x - y = 2 d + e$

Let's add $y$ $y$ to both sides of the equation:

$\Rightarrow A x - y + y = 2 d + e + y$ $Rightarrow A x - y + y = 2 d + e + y$

$\Rightarrow A x = 2 d + e + y$ $Rightarrow A x = 2 d + e + y$

Then, let's divide both sides by $A$ $A$ :

$\Rightarrow \frac{A x}{A} = \frac{1}{A} (2 d + e + y)$ $Rightarrow frac(A x)(A) = frac(1)(A) (2 d + e + y)$

$therefore x = frac(1)(A) (2 d + e + y)$