Question #f3694

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Answer 1 · 2017-08-28T01:36:17

The value of the car is never equal to zero for $x in RR$ .

The function for the value of the car is given as $v = 40,000 (1- 0.3)^(x) = 40,000 (0.7)^(x)$

We need to find when the value is zero, so let's set $v$ equal to zero:

$Rightarrow v = 0$

$Rightarrow 40,000 (0.7)^(x) = 0$

Dividing both sides by $40,000$ :

$Rightarrow (0.7)^(x) = 0$

At this point, we cannot go any further algebraically to try and solve for $x$ .

There are no real solutions to the equation.

Therefore, the value of the car is never equal to zero for $x in RR$ .