How do you solve #2x-2/3>=x-22#?

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Answer 1 · 2017-08-28T04:50:33

#xgt=21#

First, let's remove the fraction by multiplying by 3 on both sides.

#2x-2/3gt=x-22 ->#

#3(2x-2/3gt=x-22) ->#

#6x-3gt=3x-66#

Next, let's isolate like terms.

#6x-3gt=3x-66 ->#

#3xgt=63#

Now we can solve for x.

#3xgt=63 ->#

#xgt=63/3 ->#

#xgt=21#

If you have time, you can check the solution.