Question #b1829

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Question #b1829

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Answer 1 · 2017-08-29T22:30:43

Around 5.7 km

Explanation:

Use pythagorean's theorem: $c^{2} = a^{2} + b^{2}$ $c^2=a^2+b^2$
So $c = \sqrt{a^{2} + b^{2}}$ $c=sqrt(a^2+b^2)$
Since he's going left (on cartesian coordinates) 3.5km and up 4.5km, his final position would be (-3,5, 4.5) so you would just substitute
$c = \sqrt{- {3.5}^{2}, {4.5}^{2}})$ $c=sqrt(-3.5^2, 4.5^2))$
$c = \sqrt{12.25 + 20.25}$ $c=sqrt(12.25+20.25)$
$c = \sqrt{32.50}$ $c=sqrt(32.50)$
$\sqrt{32.50}$ $sqrt(32.50)$ is about 5.7km.

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Question #b1829

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