Differentiate #sin y=xy^3+ylnx#?
2 Answers
Aug 30, 2017
Explanation:
Differentiating both sides with respect to
Aug 30, 2017
Explanation:
#color(blue)"differentiate implicitly with respect to x"#
#"differentiate "xy^3" and "ylnx" using the "color(blue)"product rule"#
#cosy.dy/dx=(x.3y^2dy/dx+y^3)+(y/x+lnx.dy/dx)#
#dy/dx(cosy-3xy^2-lnx)=y^3+y/x#
#rArrdy/dx=(y^3+y/x)/(cosy-3xy^2-lnx)#
#color(white)(rAeedy/dx)=(xy^3+y)/(xcosy-3x^2y^2-xlnx)#