Question

A rectangle has a width that is twice as long as its lengths and an area of 722 square inches, how do you find the length of the diagonal?

Answer 1

See below.

Explanation:

If `x` is the length then the width is `2x`.
Area is `x` x `2x` = `2x^2` = `722 =>`x = `sqrt ((722)/2)` `=> x = 19`
Length is 19, width is 38.

By Pythagoras theorem:

Diagonal is `sqrt(19^2 + 38^2) = 42.49` `color(blue)(2.d.p.)`