How do you solve $92 = 4 (8 k - 1)$ $92= 4( 8k - 1)$ ?

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Answer 1 · 2017-08-31T09:17:13

$k = 3$ $k = 3$

$92 = 4 (8 k - 1)$ $92 = 4(8k - 1)$

Multiply the bracket

$92 = 32 k - 4$ $92 = 32k - 4$

Collect like terms

$92 + 4 = 32 k$ $92 + 4 = 32k$

$96 = 32 k$ $96 = 32k$

Divide both sides by coefficient of $k$ $k$

$96/32 = (cancel32k)/cancel32$

$96/32 = k$

$k = 3 -> Answer$

How do you solve 92= 4( 8k - 1)92=4(8k−1)92= 4( 8k - 1)?