Integrate 3x-x^2, 6<x<10?

1 Answer
Deepak Pandey
Sep 1, 2017

# int_6^10(3x-x^2)dx=-496/3#

Explanation:

We have
# int_6^10(3x-x^2)dx#
#=int_6^10 3xdx-int_6^10x^2dx#
#=3int_6^10xdx-int_6^10x^2dx#
#=3 [x^2/2]_6^10-[x^3/3]_6^10#
#=3/2×(100-36)-1/3×(1000-216)#
#=96-784/3#
#=-496/3#

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