How do you evaluate ${(10 - \sqrt[3]{- 27})}^{2}$ $(10- \root[ 3] { - 27} ) ^ { 2}$ ?

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Answer 1 · 2017-09-02T15:50:34

$169$ $169$

${(10 - \sqrt[3]{- 27})}^{2}$ $(10 - root(3)(-27))^2$

${[10 - (- 27^{\frac{1}{3}})]}^{2}$ $[10 - (-27^(1/3))]^2$

${[10 - (- 3^{3 \times \frac{1}{3}})]}^{2}$ $[10 - (-3^(3 xx1/3))]^2$

$[10 - (-3^(cancel3 xx1/cancel3))]^2$

$[10 - (-3^1)]^2$

$[10 - (-3)]^2$

$[10 + 3]^2$

$13^2$

$169$

How do you evaluate (10- \root[ 3] { - 27} ) ^ { 2}(10−3√−27)2(10- \root[ 3] { - 27} ) ^ { 2}?