How do you simplify \frac { p ^ { - 4} q ^ { - 4} r ^ { 0} \cdot p ^ { - 1} r ^ { - 2} } { ( 2p ^ { 2} q ^ { - 2} r ^ { 0} ) ^ { 3} }p4q4r0p1r2(2p2q2r0)3?

1 Answer
Sep 5, 2017

q^2/(8*p^11*r^2)q28p11r2

Explanation:

There are four rules you need to know. First, note that when you have 0 as your exponent, you are getting a result of 1 (assuming that number ≠ 0). This means:

x^0=1, if x≠0

The second is that when you raise an exponent to an exponent, you multiply the exponents. So:

(x^a)^b=x^(a*b)

When you multiply exponents, you add the exponents together. When you divide exponents, you subtract the bottom from the top. In other words:

x^a*x^b=x^(a+b)

x^a/x^b=x^(a-b)

If you are multiplying and dividing by exponents, you can combine both above to get:

(x^a*x^b)/x^c=x^(a+b-c)

Knowing these, we can simplify the expression you are given.

Since we have r^0, we can simplify that to 1. Let's expand the denominator as well.

(p^-4*q^-4*r^0*p^-1*r^-2)/(2*p^2*q^-2*r^0)^3 ->

(p^-4*q^-4*1*p^-1*r^-2)/(2*p^2*q^-2*1)^3 ->

(p^-4*q^-4*p^-1*r^-2)/(2*p^2*q^-2)^3

(p^-4*q^-4*p^-1*r^-2)/(8*p^6*q^-6)

Now that we got the first two rules out of the way, let's multiply and divide the exponents. Then we can simplify.

(p^-4*q^-4*p^-1*r^-2)/(8*p^6*q^-6) ->

(p^(-4-1-6)*q^(-4+6)*r^-2)/8 ->

(p^-11*q^2*r^-2)/8 ->

q^2/(8*p^11*r^2)