What are the oxidation states of each element that comprise the interhalogen, $I-F$ ?

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Answer 1 · 2017-09-06T13:53:46

Well, fluorine usually assumes an oxidation state of $-I$ ....and it does so here.....

The sum of the oxidation numbers EQUALS the charge on the ion, and since we gots a neutral molecule, we have therefore $stackrel(+I)I$ .

What are the oxidation numbers for the elements in $F_2$ , and for both elements in $IF_7$ ?

Answer 2 · 2017-09-06T13:54:18

Oxidation number of fluorine $= - 1$

Are you trying to spell Fluorine??

Well the Compound Name is Iodine mono fluoride or Iodine (I) fluoride $("IF")$

Since the Oxidation Number of Iodine is $1$

Hence...

Oxidation Number $rArr "IF" = 1 + F = 0$

$color(white)(xxxxxxxxxxx) rArr F = -1$

What are the oxidation states of each element that comprise the interhalogen, I-FI-F?