How many "microlitres"microlitres are in a volume of 1.22xx10^-23*cm^31.22×10−23⋅cm3?

2 Answers
Tazwar Sikder
Sep 6, 2017

1.22 times 10^(- 20)1.22×10−20 mu "L"μL

Explanation:

The volume of a single aluminium atom is 1.22 times 10^(- 23)1.22×10−23 "cm"^(3)cm3.

11 "cm"^(3)cm3 is equivalent to 0.0010.001 "L"L, or 10^(- 3)10−3 "L"L.

So, 1.22 times 10^(- 23)1.22×10−23 "cm"^(3)cm3 is equivalent to 1.22 times 10^(- 23) times 10^(- 3) = 1.22 times 10^(- 26)1.22×10−23×10−3=1.22×10−26 "L"L.

Now, to go from litres ("L")(L) to micro-litres (mu "L")(μL), we multiply the value by 10^(6)106.

Therefore, 1.22 times 10^(- 26)1.22×10−26 "L"L is equivalent to 1.22 times 10^(- 26) times 10^(6) = 1.22 times 10^(- 20)1.22×10−26×106=1.22×10−20 mu "L"μL.

anor277
Sep 6, 2017

Well, there are 1000*cm^3*L^-11000⋅cm3⋅L−1....agreed?

Explanation:

And 10^6*muL*L^-1106⋅μL⋅L−1.........

And thus 1*L-=10^6*muL-=1000*cm^31⋅L≡106⋅μL≡1000⋅cm3.

And so..............

1.22xx10^-23*cancel(cm^3)xx10^-3*cancelL*cancel(cm^-3)xx10^6*muL*cancel(L^-1)

=1.22xx10^-20*muL..........which is not a large volume......please check my calculations.....

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