If #2sinA = 1#, with #A# being an angle in quadrant #1#, what is the value of #cotA#?

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Answer 1 · 2017-09-08T03:38:10

The value of #cotA# is #sqrt(3)#.

We know that #sinA = 1/2#, and that #cotA = cosA/sinA#. Also, #cos^2x+ sin^2x = 1#. Accordingly:

#(1/2)^2 + cos^2A = 1#

#cosA = 3/4#

#cosA = sqrt(3)/2#

Accordingly,

#cotA = (sqrt(3)/2)/(1/2) = sqrt(3)#

Hopefully this helps!

Answer 2 · 2017-09-08T03:43:51

#sqrt 3#

#2 sin A = 1#, then # sin A = 1/2#

it means, opposite side #= 1# and hypotenuse #= 2#, therefore based on Pythagoras theorem, it adjacent = #sqrt (2^2 - 1^2) = sqrt(3)#

therefore

cot A = adjacent/opposite = #sqrt 3 /1 = sqrt 3#