#"1"#
#"(i)"# The force due to a magnetic field can be calculated using the formula #F = q v B sin(theta)#; where #F# is the force, #q# is the charge of the particle, #v# is the particle's velocity, #B# is the magnetic field, and #theta# is the angle between the velocity vector and magnetic field vector:
#Rightarrow F = 3.2 times 10^(- 19) times 550 times 0.045 times sin(52^(circ))#
#Rightarrow F = 3.2 times 10^(- 19) times 24.75 times 0.7880107536#
#Rightarrow F = 3.2 times 10^(- 19) times 19.503266152#
#Rightarrow F = 6.241045169 times 10^(- 18)#
#therefore F = 6.24 times 10^(- 18)#
Therefore, the force acting on the particle due to the field is around #6.24 times 10^(- 18)# #"N"#.
#"(ii)"# Now, we must find the acceleration of the particle due to the magnetic force acting on it.
Let's use the formula #F = ma#:
#Rightarrow = 6.24 times 10^(- 18) = 6.6 times 10^(- 27) times a#
#Rightarrow 945,454,545.45 = a#
#therefore a = 9.46 times 10^(8)#
Therefore, the acceleration on the particle due to #vec(F_(B))# is around #9.46 times 10^(8)# #"m s"^(- 2)#.
#"(iii)"# As the particle accelerates, it increases in speed.
