Hi, Can you help me please? Thank you!
Identify the vertex and the axis of symmetry of the graph of the function #y = 2(x+2)^2 - 4#
A)
vertex: (-2, 4);
axis of symmetry: x = -2
B)
vertex: (2, -4);
axis of symmetry: x = 2
C)
vertex: (-2, -4);
axis of symmetry: x = -2
D)
vertex: (2, 4);
axis of symmetry: x = 2
Identify the vertex and the axis of symmetry of the graph of the function
A)
vertex: (-2, 4);
axis of symmetry: x = -2
B)
vertex: (2, -4);
axis of symmetry: x = 2
C)
vertex: (-2, -4);
axis of symmetry: x = -2
D)
vertex: (2, 4);
axis of symmetry: x = 2
1 Answer
Answer is (c).
Explanation:
Luckily, the equation was given to us in vertex form. This makes determining the vertex a lot easier.
In vertex form, the
Therefore, with an
#x+2=0#
#x=-2#
This gives us
As for the
Put this all together and our vertex is
The axis of symmetry is basically the
If we graph the equation, we can confirm our vertex.
graph{y=2(x+2)^2-4 [-10, 10, -5, 5]}
Therefore, the correct answer is (c).
Hope this helps :)