Question

A gas at constant volume has 25 J of heat added to it. What is the work done by the gas?

Answer 1

`25` joule

Explanation:

BY FIRST LAW OF THERMODYNAMICS ,

`DeltaU= q+w`
now volume is also constant,therefore,initial and final temperatures are also same .

Threrefore,

`DeltaU=0`; `q=-w`

Hence 25 joule. Relatively you apply sign convention.