How do you solve $-5m ^ { 2} + 2m + 39= 0$ ?

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Answer 1 · 2017-09-11T16:34:24

$1/5±(2i)/5sqrt194$

$x=(-b±sqrt(b^2-4ac))/(2a)$

a = -5
b=2
c=39

Let's plug the numbers in and solve

$x=(-(2)±sqrt((2)^2-4(5)(39)))/(2*(-5)) ->$

$x=(-2±sqrt(4-780))/-10 ->$

$(-2±sqrt(-776))/-10 ->$

$(-2±4isqrt194)/-10 ->$

$1/5±(2i)/5sqrt194$

You get imaginary roots for this equation. If you have not learned about imaginary roots/numbers, the answer would be that there are no roots.

How do you solve -5m ^ { 2} + 2m + 39= 0-5m ^ { 2} + 2m + 39= 0?