Question #09738

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Answer 1 · 2017-09-11T22:18:09

#color(blue)(13a - 2 )#

#16( a - 2 ) + 3( 10 - a )#

Multiply brackets by the value outside of them to remove them.

#16a - 32 + 30 -3a#

Collect like terms:

#16a -3a -32 + 30 = color(blue)(13a -2) #

Answer 2 · 2017-09-11T22:18:37

#=13a-2#

We start using the expansion method where:
#a(b+c)=ab+ac#

#rarr16(a-2) +3(10-a)=16a-32+30-3a#
Grouping the terms with unknowns and numbers to add/subtract them:
#16a-3a-32+30#
#=13a-2#

Supposing that your question is to find the roots or find values of a such that #6(a-2) +3(10-a)=0#:

#6(a-2) +3(10-a)=0#
#rarr 13a-2=0#

Adding 2 to both sides:
#13a-2+2=0+2#
#13a=2#

Dividing both sides by 13:
#13a/13=2/13#
#rarr a=2/13#