Question #09738

2 Answers
Sep 11, 2017

13a2

Explanation:

16(a2)+3(10a)

Multiply brackets by the value outside of them to remove them.

16a32+303a

Collect like terms:

16a3a32+30=13a2

Sep 11, 2017

=13a2

Explanation:

We start using the expansion method where:
a(b+c)=ab+ac

16(a2)+3(10a)=16a32+303a
Grouping the terms with unknowns and numbers to add/subtract them:
16a3a32+30
=13a2

Supposing that your question is to find the roots or find values of a such that 6(a2)+3(10a)=0:

6(a2)+3(10a)=0
13a2=0

Adding 2 to both sides:
13a2+2=0+2
13a=2

Dividing both sides by 13:
13a13=213
a=213