Question #5155e

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Answer 1 · 2017-09-12T21:07:31

${- \frac{a}{2}, a, 2 b}$ ${- frac(a)(2), a, 2 b}$

We have: $5 (x - a) (2 b - x) (2 x + a) = 0$ $5 (x - a) (2 b - x) (2 x + a) = 0$

Dividing through by $5$ $5$ :

$\Rightarrow (x - a) (2 b - x) (2 x + a) = 0$ $Rightarrow (x - a) (2 b - x) (2 x + a) = 0$

Using the null factor law:

$Rightarrow x - a = 0 therefore x = a$

$or$

$Rightarrow 2 b - x = 0 Rightarrow 2 b = x therefore x = 2 b$

$or$

$Rightarrow 2 x + a = 0 Rightarrow 2 x = - a therefore x = - frac(a)(2)$

Therefore, the solution set to the equation is ${- frac(a)(2), a, 2 b}$ .