How do you evaluate -1- 2v = - 6v - 19+ 2v12v=6v19+2v?

1 Answer
Sep 13, 2017

-99

Explanation:

−1−2v=−6v−19+2v12v=6v19+2v is also the same as

−1color(pink)+−2v=−6vcolor(pink)+−19+2v1+2v=6v+19+2v. It is also the same as

color(pink)2color(pink)vcolor(pink)-color(pink)1=−6v+color(pink)2color(pink)vcolor(pink)+color(pink)(-19)2v1=6v+2v+19

So,

−2v−1=color(pink)((−6v+2v))+−192v1=(6v+2v)+19

Which is also

−2v−1=color(pink)−color(pink)4color(pink)v+−192v1=4v+19

−2v−1=−4vcolor(pink)−192v1=4v19

Then we will add 4v4v to both sides.

−2v−1color(pink)+color(pink)4color(pink)v=−4v−19color(pink)+color(pink)4color(pink)v2v1+4v=4v19+4v

So,

2v−1=−192v1=19

Then we add 11 to both sides.

2v−1color(pink)+color(pink)1=−19color(pink)+color(pink)12v1+1=19+1

That means 2v=−182v=18

Divide both sides by 22

:. v=-9