How do you evaluate #-1- 2v = - 6v - 19+ 2v#?

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Answer 1 · 2017-09-13T12:52:33

#-9#

#−1−2v=−6v−19+2v# is also the same as

#−1color(pink)+−2v=−6vcolor(pink)+−19+2v#. It is also the same as

#color(pink)2color(pink)vcolor(pink)-color(pink)1=−6v+color(pink)2color(pink)vcolor(pink)+color(pink)(-19)#

So,

#−2v−1=color(pink)((−6v+2v))+−19#

Which is also

#−2v−1=color(pink)−color(pink)4color(pink)v+−19#

#−2v−1=−4vcolor(pink)−19#

Then we will add #4v# to both sides.

#−2v−1color(pink)+color(pink)4color(pink)v=−4v−19color(pink)+color(pink)4color(pink)v#

So,

#2v−1=−19#

Then we add #1# to both sides.

#2v−1color(pink)+color(pink)1=−19color(pink)+color(pink)1#

That means #2v=−18#

Divide both sides by #2#

#:. v=-9#