Question #0d4e0

1 Answer
Tazwar Sikder
Sep 18, 2017

#F = 22.5# #"N"#

Explanation:

Let's use the equation #F = B I L sin(theta)#; where #B# is the magnitude of the magnetic field, #I# is the current carried by the wire, #L# is the length of the wire, and #theta# is the angle the wire makes with the magnetic field:

#Rightarrow F = 1.24# #"T" cdot 12.8# #"A" cdot 1.99# #"m" cdot sin(45.4^(circ))#

#Rightarrow F = 1.24# #"N" cdot "s" cdot "C"^(- 1) cdot "m"^(- 1) cdot 12.8# #"A" cdot 1.99# #"m" cdot 0.71202604599#

#Rightarrow F = 1.24# #"N" cdot "s" cdot "A"^(- 1) cdot "s"^(- 1) cdot "m"^(- 1) cdot 25.472# #"A" cdot "m" cdot 0.71202604599#

#Rightarrow F = 31.58528# #"N" cdot 0.71202604599#

#Rightarrow F = 22.48954203# #"N"#

#therefore F = 22.5# #"N"#

Therefore, the magnetic force on the wire is around #22.5# #"N"#

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