Question

Question #0d4e0

Answer 1

`F = 22.5` `"N"`

Explanation:

Let's use the equation `F = B I L sin(theta)`; where `B` is the magnitude of the magnetic field, `I` is the current carried by the wire, `L` is the length of the wire, and `theta` is the angle the wire makes with the magnetic field:

`Rightarrow F = 1.24` `"T" cdot 12.8` `"A" cdot 1.99` `"m" cdot sin(45.4^(circ))`

`Rightarrow F = 1.24` `"N" cdot "s" cdot "C"^(- 1) cdot "m"^(- 1) cdot 12.8` `"A" cdot 1.99` `"m" cdot 0.71202604599`

`Rightarrow F = 1.24` `"N" cdot "s" cdot "A"^(- 1) cdot "s"^(- 1) cdot "m"^(- 1) cdot 25.472` `"A" cdot "m" cdot 0.71202604599`

`Rightarrow F = 31.58528` `"N" cdot 0.71202604599`

`Rightarrow F = 22.48954203` `"N"`

`therefore F = 22.5` `"N"`

Therefore, the magnetic force on the wire is around `22.5` `"N"`