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Answer 1 · 2017-09-18T11:51:27

$F = \frac{G \cdot M_{1} \cdot M_{2}}{r^{2}}$ $F=(G*M_1*M_2)/r^2$

The force of attraction between two bodies having masses is called as Gravitational force.

Gravitational force is directly proportional to product of masses of the two bodies .

$F α M_{1} \cdot M_{2}$ $F alpha M_1*M_2$

Gravitational force is inversely proportional to the square of the distance between the two bodies.

$F α \frac{1}{r^{2}}$ $Falpha1/r^2$

where,
r is the distance between two bodies.

Combining these two relations,
$F α \frac{M_{1} \cdot M_{2}}{r^{2}}$ $Falpha(M_1*M_2)/r^2$

After inserting a proportionality constant in this equation we arrived at the relation,

$F = \frac{G \cdot M_{1} \cdot M_{2}}{r^{2}}$ $F=(G*M_1*M_2)/r^2$

Where ,

G is the Universal gravitational constant whose value is $6.67 \times 10^{- 11} N m^{2} k g^{- 2}$ $6.67xx10^-11 Nm^2kg^-2$