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Answer 1 · 2017-09-20T13:43:24

$\frac{1}{11}$ $1/11$

the first Urn

$3 White, 6 Yellow$ $3" White", 6" Yellow"$

$: P_{1} (W) = \frac{3}{9} = \frac{1}{3}$ $:P_1(W)=3/9=1/3$

the second urn

$3 White, 8 Yellow$ $3" White", 8" Yellow"$

$P_{2} (W) = \frac{3}{11}$ $P_2(W)=3/11$

these events are independent from each other so the combined probability is

$P (W W) = P_{1} (W) \times P_{2} (W)$ $P(WW)=P_1(W)xxP_2(W)$

$= \frac{1}{3} \times \frac{3}{11} = \frac{1}{11}$ $=1/3xx3/11=1/11$