A student calculates the density of iron as 6.6 g/cm3 using lab data for mass and volume. A handbook reveals that the correct value is 7.57 g/cm3. What is the percent error?

1 Answer
Sep 20, 2017

% "error" = 12.8%%error=12.8%

Explanation:

Percent error is calculated using the following formula:

Rightarrow % "error" = |frac("experimental value" - "theoretical value")("theoretical value")| cdot 100%error=experimental valuetheoretical valuetheoretical value100

This formula can be refined as:

Rightarrow % "error" = |frac("experimental value")("theoretical value") - frac("theoretical value")("theoretical value")| cdot 100%error=experimental valuetheoretical valuetheoretical valuetheoretical value100

Rightarrow % "error" = |frac("experimental value")("theoretical value") - 1| cdot 100%error=experimental valuetheoretical value1100

Now, let's substitute the relevant values into the formula:

Rightarrow % "error" = |frac(6.6" g/cm"^(3))(7.57" g/cm"^(3)) - 1| cdot 100%error=∣ ∣6.6 g/cm37.57 g/cm31∣ ∣100

Rightarrow % "error" = |0.8718626156 - 1| cdot 100%error=|0.87186261561|100

Rightarrow % "error" = |- 0.1281373844| cdot 100%error=|0.1281373844|100

Rightarrow % "error" = 0.1281373844 cdot 100%error=0.1281373844100

Rightarrow % "error" = 12.81373844%%error=12.81373844%

therefore % "error" approx 12.8%

Therefore, the percent error is around 12.8%.