How do you solve #5< 4x + 3\leq 11#?

2 Answers
Sep 21, 2017

What you do to the center to make it become only x, you do to all 3.

Explanation:

Given: #5< 4x + 3 <= 11#

What you do to the center to make it become only x, you do to all 3.

Subtract 3:

#2 < 4x <= 8#

Divide by 4:

#1/2< x <= 2#

Solved

Sep 21, 2017

#1/2< x <=2#

Explanation:

Subtract 3 from both sides:

#color(green)(2)<4x<=color(green)(8) #

Divide 4 from both sides:

#color(green)(2/4)< x <=color(green)(8/4)#

Simplify:

#color(green)(1/2)< x <=color(green)(2)#