How do you factor #62x + 11x ^ { 2} + 10x#?

1 Answer
Sep 23, 2017

#x(11x+72)#

Explanation:

First, we will apply this: #x^2=x x#
Therefore, #62x+11x^2+10x=62x+11x x+10x#

We will then factor out common term #x#.

From #62x+11x x+10x# to #x(62+11x+10)#.
We then group like terms:

#x(11x+10+62)#

And add #10+62# to be #72#.

So the equation will be #x(11x+72)#.