Question #a2291

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Answer 1 · 2017-09-25T01:35:12

See below.

This is the equation/formula you want to use:

$d=m/V$ ,

where $d$ is density in $"k"*"gm"^-3$ , $m$ is the mass in $"kg"$ , and $V$ is the volume in $"m"^3$ .

The first step is to convert $40 " g"$ to $"kg"$ using dimensional analysis:

$40" g"*((10^-3" kg")/(1" g"))=4.0*10^-2 " kg"$

Now, let's convert $16 " cm"^3$ to $"m"^3$ (this is where it gets tricky, pay close attention):

$16" cm"^3 * ((1" m")/(100" cm"))^3 = 1.6 * 10^-5 " m"^3$

Now, let's take these two values and plug them into our density formula mentioned above:

$d=m/V$

$d=(4.0*10^-2 " kg")/(1.6 * 10^-5 " m"^3)$

$d=2.5*10^2" kg"*"m"^-3$

I hope that helps!